At the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 65 m/s. The driver of the Thunderbird realizes that she must make a pit stop, and she slows to a stop over a distance of 222 meters. She spends 8 seconds in the pit and then accelerates out, reaching her previous speed of 65 m/s after a distance of 340. At this point, how far has the Thunderbird fallen behind the Mercedes Benz, which has continued at a constant speed?
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Accessories March 20th 2011
March 20th, 2011 at 8:16 am
The total distance traveled by Thunder with varying speed is
[340 + 222] = 562 m
Time taken by him to travel this distance is 2 S / u = 2*562 / 65
The distance traveled by the other in this time is
65* {2*562 / 65} = 2 * 562m
Hence distance of separation between them is 562m.
The distance traveled by the other in the 8s rest of Thunder is 8*65.
Total distance of separation = 562 + 8*65.
= 1082 m
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Or simply s1 + s2 + 8u
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By askme.